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The relative offset used for jumping in a loop instruction is encoded by a single byte.

1. What is the largest possible backward jump?
2. What is the largest possible forward jump?

A)
1. -127
2. +128

B)
1. -127
2. +127

C)
1. -128
2. +127

D)
1. -128
2. +128

User Cowls
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1 Answer

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Final answer:

The relative offset for a loop instruction encoded by a single byte ranges from -128 to +127 due to the two's complement binary representation which allocates half of the 256 values to the negative range and the other half to the positive, except the last positive value (+128) which is not representable. correct answer is C.

Step-by-step explanation:

The relative offset for a loop instruction that is encoded in a single byte can have a range of values from -128 to +127. This is because a single byte can represent 256 different values (28), and when used for signed numbers, it is typically divided into a negative range and a positive range. In two's complement binary representation, the negative range goes from -128 to -1, and the positive range goes from 0 to +127.

The provided equations, such as Junction c: I₁+Iā‚‚ - 13 = 0, and Loop abcde fa: I₁ (32) 1ā‚‚ (822) = -1.8 V, appear to relate to circuit analysis and are likely part of a series of Kirchhoff's circuit laws problems or similar electrical engineering exercises. However, they are not directly related to the concept of the jumping range in assembly language or machine code.

User VladH
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