The function f(x) = -2 represents a constant linear function since the slope (m) is 0, indicating a horizontal line. The expression is simplified as f(x) = -2.
Given the values of x and f(x), we can determine whether f(x) represents a linear function. If it does, we can express it in the form f(x) = mx + b.
Let's calculate the slope (m) using two points, (-1, -2) and (2, -2):
![\[ m = \frac{\text{change in } y}{\text{change in } x} = (-2 - (-2))/(-1 - 2) = (0)/(-3) = 0 \]](https://img.qammunity.org/2024/formulas/mathematics/college/uu3rr475ixd6d4a7rm9bvdk68hhqsyfrx5.png)
Since the slope (m) is 0, it indicates a constant function. Now, let's find the y-intercept (b) using any point, e.g., (0, -2):
![\[ f(0) = 0 \cdot m + b \]](https://img.qammunity.org/2024/formulas/mathematics/college/oglr0p6uevtj29syr1ffkgpjl6o4n0w1kb.png)
-2 = 0 + b
b = -2
Now, we can express f(x) in the form f(x) = mx + b:
![\[ f(x) = 0 \cdot x - 2 = -2 \]](https://img.qammunity.org/2024/formulas/mathematics/college/xhukewt79uif2kvgrx2e34r63wfng5ov1p.png)
So, the correct choice is:
![\[ \text{A. } f(x) = -2 \]](https://img.qammunity.org/2024/formulas/mathematics/college/bp5xn0r78j1dwlbhxaqy262emse44y1qsa.png)