Final answer:
The energy fluence of 1.17-MeV photons over 24 hours cannot be determined without the photon flux. The energy of the photon in joules is 1.875×10-13 J. Further information is needed to calculate the energy fluence in erg/cm2 and J/m2.
Step-by-step explanation:
To calculate the energy fluence of 1.17-MeV photons over a period of 24 hours, we need to convert the photon energy into more common units. The energy fluence is the energy per unit area delivered by the radiation over a specified time period.
The energy of the photon given is 1.17 MeV (Mega-electron Volts). First, we should convert this into joules. Since 1 eV = 1.602×10-19 J, then 1.17 MeV = 1.17×106 eV = 1.17×106×1.602×10-19 J = 1.875×10-13 J.
To find energy fluence (Φ), we need to consider the number of photons hitting a specific area over the total time. Assuming a constant flux, the fluence would be the photon energy times the number of photons per square centimeter per second, integrated over the time period of interest (24 hours or 86,400 seconds). Without the flux value, we cannot provide an exact numeric answer as more information is needed about the number of photons.
Once the fluence in joules is calculated, it can then be converted to ergs as 1 J = 107 ergs, and for area conversion from square centimeters to square meters, recall that 1 m2 = 104 cm2. The resulting units for energy fluence would be expressed in erg/cm2 and J/m2.