Final answer:
To sketch a graph of position versus time for a mouse moving back and forth in a corridor, the graph should depict the changes in slope corresponding to the changes in the mouse's speed, including constant speeds, accelerations, decelerations, and reversals of direction.
Step-by-step explanation:
I will sketch a reasonable graph of position (s) versus time (t) for a mouse trapped in a narrow corridor. The mouse moves with a constant speed of 1.2 m/s, then slows down to 0.6 m/s, then speeds up to 2.0 m/s, and finally slows to a stop before reversing direction and speeding up to 1.2 m/s.
Starting at time zero, the s versus t graph will slope upwards at a consistent angle representing a velocity of 1.2 m/s. When the mouse slows to 0.6 m/s, the slope will decrease showing a reduced inclination until it reaches 0.6 m/s. Shortly after, the slope of the graph will steepen, indicating an increase in speed up to 2.0 m/s.
Eventually, the graph will plateau as the mouse comes to a stop. There will be an instantaneous change in the slope direction, indicating a reversal of movement, and the graph will slope negatively as the mouse speeds up to 1.2 m/s in the opposite direction.