Final answer:
The emitted power per square meter of peak intensity for a 3000 Kelvin source is 1.365 × 105 W/m2.
Step-by-step explanation:
To find the emitted power per square meter of peak intensity for a 3000 Kelvin source, you need to use the Stefan-Boltzmann Law. This law states that the power emitted by a perfect black body is directly proportional to the fourth power of its temperature.
The equation for the power emitted per square meter by a black body is given by P = σT4, where P is the power, σ is the Stefan-Boltzmann constant (5.67 × 10-8 W/m2K4), and T is the temperature in Kelvin.
Substituting the given temperature of 3000 Kelvin into the equation, we can calculate the emitted power per square meter.
Power emitted per square meter = 1.365 × 105 W/m2