Final answer:
The system of linear equations 4(m - n) = 0 has an infinite number of ordered pairs $(m, n)$ as solutions, where m and n can take any value.
Step-by-step explanation:
The given system of linear equations is:
4(m - n) = 0
To find the number of ordered pairs $(m, n)$ that satisfy this system, we need to solve the equation for m and n in terms of each other.
First, let's isolate the variable m:
4m - 4n = 0
Next, let's isolate the variable n:
n = (1/4)m
Now we can see that for any value of m, we can find a corresponding value of n by substituting it into the equation above. This means that there are an infinite number of ordered pairs $(m, n)$ that satisfy the system. In other words, the system has an infinite number of solutions.