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a bowl contained 16.1 grams of salt then greg poured 44.87 grams how much salt doed the bowl contain now

User Belema
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1 Answer

1 vote

Final answer:

To find the total amount of salt in the bowl after Greg poured an additional 44.87 grams, simply add it to the initial 16.1 grams to get a new total of 60.97 grams.

Step-by-step explanation:

To calculate how much salt the bowl contains after Greg poured 44.87 grams, we need to add this amount to the initial amount of 16.1 grams. The solving process is simply a matter of adding the two amounts together. So, the calculation will be:

16.1 g (initial amount) + 44.87 g (amount added) = 60.97 g of salt in the bowl now.

Note that the information provided regarding the remaining amount after solving, NaCl solution preparation, saturated solution, van 't Hoff factor, significant figures, molarity calculation, and sea water concentration was not directly relevant to solving this particular question.

To find out how much salt the bowl contains now, we need to add the amount of salt that Greg poured to the initial amount of salt in the bowl. So, the total amount of salt in the bowl now is 16.1 grams + 44.87 grams = 61.97 grams.

User Sebu
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