Question

If 200 grams of water is to be heated from 24 degrees to 100 degrees C to make a cup of tea how much heat must be absorbed by the Ayer to make this happen? The specific heat of water is 4.18

Answer 1

The amount of heat that must be absorbed to heat water from 24 degrees to 100 degrees C is 63536 J

How to calculate the amount of heat absorbed?

We shall begin by calculating the temperature change of the water that occurred in the process. This is shown below:

• Initial temperature (T₁) = 24 degrees C
• Final temperature (T₂) = 100 degrees C
• Temperature change (ΔT) =?

Temperature change = Final - initial

= 100 - 24

= 76 degrees C

Finally, we shall calculate the heat absorbed. This is shown below:

• Mass of water (M) = 200 grams
• Temperature change (ΔT) = 76 degrees C
• Specific heat capacity of water (C) = 4.18 J/gºC
• Heat absorbed (Q) =?

Q = MCΔT

= 200 × 4.18 × 76

= 63536 J