Final answer:
150g of sodium reacts with chlorine gas to produce 381.10g of sodium chloride.
Step-by-step explanation:
When 150g of sodium reacts with an excess of chlorine gas, according to the reaction equation 2 Na (s) + Cl₂(g) → 2 NaCl (s), the amount of sodium chloride produced can be calculated using stoichiometry.
First, we need to calculate the moles of sodium used. The atomic mass of sodium (Na) is 22.99g/mol. Therefore, 150g Na ÷ 22.99g/mol = 6.52 moles of Na. According to the equation, two moles of Na will produce two moles of NaCl. Therefore, 6.52 moles of Na will produce 6.52 moles of NaCl.
The formula mass of NaCl is 58.44g/mol. Multiplying the moles of NaCl by its formula mass gives the mass of NaCl produced: 6.52 moles × 58.44g/mol = 381.10g of NaCl. Hence, 150g of sodium produces 381.10g of sodium chloride when reacted with an excess of chlorine gas.