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4 votes
What is the largest 5-digit number that is a multiple of both 4 and 9?

(a) 99990
(b) 99981
(c) 99972
(d) 99963
(e) 99954

User Kewal Shah
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2 Answers

3 votes

Answer:

99972

Step-by-step explanation:

For a number to be a multiple of 4, the last two digits must form a number divisible by 4.

72/4 = 18

For a number to be a multiple of 9, it must be divisible by 3. Therefore, the sum of the digits must be a multiple of 3

9 + 9 + 9 + 7 + 2 = 36

3 x 12 = 36

6 votes

Final answer:

The largest 5-digit number that is a multiple of both 4 and 9 is 99972, as it meets the divisibility tests for both numbers.

Step-by-step explanation:

The question asks for the largest 5-digit number that is a multiple of both 4 and 9. To be a multiple of 4, a number must have its last two digits be a multiple of 4. To be a multiple of 9, the sum of the number's digits must be a multiple of 9. Among the choices, only 99972 is divisible by both 4 and 9. The divisibility test for 4 confirms that 72 is a multiple of 4, and adding the individual digits of 99972 (9+9+9+7+2 = 36) shows that the sum is a multiple of 9. Therefore, the largest 5-digit number that satisfies the conditions is 99972.

User Jatnna
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