Final answer:
To calculate the volume of oxygen gas produced by the decomposition of KClO₃, use stoichiometry and the ideal gas law. The answer is 0.448 L of oxygen gas.
Step-by-step explanation:
To calculate the volume of oxygen gas produced by the decomposition of KClO₃, we need to use stoichiometry. First, calculate the moles of KClO₃ by dividing the mass by the molar mass. Next, use the balanced equation to find the mole ratio between KClO₃ and O₂. Finally, use the ideal gas law to calculate the volume of O₂ at STP. The answer is 0.448 L of oxygen gas.