To graph the line with a slope of 3 passing through the point (3, -3), plot the given point, calculate the y-intercept using the slope-intercept form, and then plot additional points on the line. Finally, connect the plotted points to obtain the graph of the line.
To graph the line with a slope of 3 passing through the point (3, -3), we can follow these steps:
1. Plot the given point (3, -3) on a coordinate plane. This point represents one of the coordinates on the line.
2. Use the slope-intercept form of a linear equation, y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is 3.
3. Substitute the coordinates (x, y) of the given point into the equation. We have -3 = 3(3) + b.
4. Solve for the y-intercept, b. -3 = 9 + b. By subtracting 9 from both sides, we find that b = -12.
5. Now we have the equation of the line: y = 3x - 12.
6. Plot additional points on the line by choosing different x-values and calculating the corresponding y-values using the equation. For example, when x = 0, y = -12. When x = 2, y = -6.
7. Connect the plotted points with a straight line. This line represents the graph of the equation y = 3x - 12.
The question probable may be:
Graph the line with slope 3 passing through the point (3, -3).