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Simplify 3√(32x⁴.z). Assume x and z are nonnegative.

A. 12√(x².z)
B. 48x²√(x².z)
C. 48x²√(2z)
D. 12x²√(2z)

User Jinwon
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1 Answer

2 votes

Final answer:

The expression 3√(32x⁴z) is simplified by factoring and taking cube roots of perfect cubes, resulting in 6x²√(2z). However, this result does not match any of the provided options, implying a possible typo in the question.

Step-by-step explanation:

The student is asking to simplify the expression 3√(32x⁴z), assuming x and z are nonnegative.

  1. Factor 32 into 2³ * 2 because 32 is 2 raised to the 5th power.
  2. Notice that x⁴ can be written as (x²)² which is a perfect square.
  3. Since we have a cube root, we can take the cube root of 2³ out of the radical, which gives us 2, and we can take x² out of the radical because it is a perfect square.
  4. After taking the cube root of the perfect cubes, we are left with 2x² outside the radical and still have a 2 and z under the radical. Multiply these by the prefactor 3 to simplify further.

Thus, the simplified expression is 3 * 2x² * √(2z) or 6x²√(2z). But since none of the options match this result, it seems there might be a typo in the given options or in the original expression.

User Jeeyoungk
by
7.8k points
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