Final answer:
The molarity of the NaF solution is calculated by dividing the number of moles of NaF, which is 0.476 moles, by the volume of the solution, which is 0.5000 L, resulting in a molarity of 0.952 M.
Step-by-step explanation:
To calculate the molarity of the NaF solution, we will use the given mass of NaF and its molar mass, as well as the volume of the solution.
The molar mass of NaF is 41.99 g/mol. With a mass of 20.0 g of NaF, we can determine the number of moles of NaF:
Number of moles = Mass of NaF / Molar mass of NaF = 20.0 g / 41.99 g/mol
Number of moles = 0.476 moles of NaF
To find the molarity (M), which is the number of moles of solute per liter of solution, we use the formula:
Molarity (M) = Number of moles / Volume of solution in liters
Molarity (M) = 0.476 moles / 0.5000 L
Molarity (M) = 0.952 M
The molarity of the NaF solution is therefore 0.952 M.