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Y to the second power+4y+3 when y=7

User Zjhui
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Final answer:

To find the value of 'y to the second power + 4y + 3' when y=7, you substitute 7 into the equation and simplify to get 49 + 28 + 3, which equals 80.

Step-by-step explanation:

The student's question involves evaluating a quadratic expression when y=7. Specifically, the student needs to evaluate y² + 4y + 3 for the given value of y. Here is the step-by-step process:

  1. First, plug in the value of y into the equation: (7)² + 4*(7) + 3.
  2. Next, square the value of y: 49.
  3. Then, multiply 4 by y: 4*7 = 28.
  4. Finally, add all the terms together: 49 + 28 + 3 = 80.

So, when y=7, the value of the expression y² + 4y + 3 is 80.

User Ivansaul
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