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The graph of h(x) = –log5(x + 5). Graph of h of x that begins in quadrant two and decreases rapidly following the vertical line which is 5 units to the left of the y-axis. The curve crosses the x-axis 4 units to the left of the origin and crosses the y-axis one unit below the origin and then continues to decrease to the right in quadrant 4. What are the intercepts and asymptote of h(x)? Explain how to find these using the graph.

User Yoshiyahu
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The function h(x) = -log base 5 of (x + 5) has intercepts at (-4, 0) and (0, -1), and its asymptote is a vertical line at x = -5.

The given function is h(x) = -log base 5 of (x + 5). To determine the intercepts and asymptote using the graph, we interpret the information provided.

x-Intercept: The curve crosses the x-axis 4 units to the left of the origin. To find this intercept, we set h(x) to zero and solve for x: 0 = -log base 5 of (x + 5). Solving this equation gives x = -4, so the x-intercept is (-4, 0).

y-Intercept: The curve crosses the y-axis one unit below the origin. Setting x to zero, we find h(0) = -log base 5 of (5) = -1, so the y-intercept is (0, -1).

Asymptote: The curve decreases rapidly following the vertical line 5 units to the left of the y-axis. This vertical line is a vertical asymptote for the function. In general, for a logarithmic function of the form -log base b of (x + c), the vertical asymptote is given by x = -c. Therefore, in this case, the asymptote is x = -5.

In summary, the intercepts of h(x) = -log base 5 of (x + 5) are (-4, 0) for the x-axis and (0, -1) for the y-axis. The asymptote is a vertical line at x = -5, five units to the left of the y-axis.

The graph of h(x) = –log5(x + 5). Graph of h of x that begins in quadrant two and-example-1
User Ian Henry
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