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What is the oxidation number of O2 and N2 based in the reaction equations?

What is the oxidation number of O2 and N2 based in the reaction equations?-example-1
User Happy
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O in CO is -2 C in CO is +2 O in CO₂ is -2 C in CO₂ is +4

O₂ is 0 N₂ is 0 N in NO₂ is +4 O in NO₂ is -2

Reaction #1: exothermic Reaction #2: exothermic

What more can be said about the oxidation number of the element in the reaction?

Oxygen typically has an oxidation number of -2.

The compound is neutral, so the sum of oxidation numbers must be 0. Therefore, carbon (C) in CO must have an oxidation number of +2.

In CO₂, the total oxidation number for oxygen is 2(-2) = -4. To balance this, the oxidation number of carbon must be +4.

In a diatomic molecule like O₂, the oxidation number for oxygen is 0.

N2 (Nitrogen Gas):

Similarly, in diatomic nitrogen (N₂), the oxidation number for nitrogen is 0.


Reaction 1 (2NO₂(g) + 4CO(g) → N₂(g) + 4CO₂(g) + 1198.4 kJ):

This reaction is exothermic because it releases energy (1198.4 kJ).

Reaction 2 (2CO(g) + O₂(g) → 2CO2(g) + 566.0 kJ):

This reaction is also exothermic, as it releases energy (566.0 kJ).

User Kviktor
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