Question

A dragster crosses the finish line with a velocity of 140 m/s. Calculate the dragster's deceleration if it comes to a stop within 4 seconds. What is the initial velocity, and what distance does it cover during this deceleration?

Answer 1

The deceleration of the dragster is -35 m/s². The initial velocity is 140 m/s, and the distance covered during the deceleration is 280 m.

Step-by-step explanation:

To find the deceleration of the dragster, we can use the equation:

acceleration = (final velocity - initial velocity) / time

Given that the final velocity is 0 m/s, the initial velocity is 140 m/s, and the time is 4 seconds, we can substitute these values into the equation:

acceleration = (0 m/s - 140 m/s) / 4 s

Simplifying the equation, we have:

acceleration = -140 m/s / 4 s

acceleration = -35 m/s²

The dragster's initial velocity is 140 m/s. To find the distance it covers during the deceleration, we can use the equation:

distance = (initial velocity + final velocity) / 2 * time

Substituting the given values into the equation, we have:

distance = (140 m/s + 0 m/s) / 2 * 4 s

Simplifying the equation, we get:

distance = 70 m/s * 4 s

distance = 280 m