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Is 1−sin² (θ) a difference of squares?
A) Yes

B) No

User Gpwr
by
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1 Answer

2 votes

Final answer:

The expression 1−sin²(θ) is not a difference of squares; rather it aligns with the Pythagorean identity and can be rewritten as cos²(θ). The correct option is B) No.

Step-by-step explanation:

The expression 1−sin²(θ) is not a difference of squares because a difference of squares takes the form of a²−b², which represents the difference between the squares of two expressions. The expression 1 cannot be written as a square of a trigonometric function. However, it is related to the Pythagorean identity, which is cos²(θ) + sin²(θ) = 1, which can be rearranged to 1 − sin²(θ) = cos²(θ). So, the correct form of the expression utilizing trigonometric identities is cos²(θ), not a difference of squares.

Therefore, in reference to your question: Is 1−sin² (θ) a difference of squares? The correct option is B) No.

User Jordie
by
8.4k points

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