Final answer:
To evaluate the limit limₓ→ 2π 4(π−2x)tan(x), substitute 2π for x, simplify the expression, and evaluate the tangent function. The limit is 0.
Step-by-step explanation:
To evaluate the limit limₓ→ 2π 4(π−2x)tan(x), we substitute 2π for x in the expression:
4(π−2x)tan(x)
By plugging in x = 2π, we get:
4(π−2(2π))tan(2π)
Simplifying, we have:
4(π−4π)tan(2π)
And further simplifying:
4(-3π)tan(2π)
Finally, we evaluate the tangent function at 2π, which is 0:
4(-3π)(0)
Since anything multiplied by 0 is 0, the limit limₓ→ 2π 4(π−2x)tan(x) equals 0. Therefore, the answer is A) 0.