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Given x = (2/3)t³, y = t² − 2, 0 ≤ t ≤ 8, find dy/dt.

a) t²
b) 2t
c) 3t² - 2
d) 2t²

User Nate Bosch
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1 Answer

6 votes

Final answer:

To find dy/dt for the function y = t² − 2, differentiate each term separately using the power rule. Since the derivative of t² is 2t and the derivative of a constant is 0, the correct derivative dy/dt is 2t.

"the correct option is approximately option B"

Step-by-step explanation:

The question asks us to find the derivative of y with respect to t, that is, dy/dt, given that y = t² − 2. To find dy/dt, we need to use differentiation, which is a tool in calculus for finding the rate at which a function is changing at any given point. Using the power rule of differentiation, we differentiate each term of the function separately. In this case, the derivative of t² is 2t (since the power rule states that d/dt of t to the power of n is n times t to the power of n-1) and the derivative of a constant is 0. Therefore, the derivative of y with respect to t is:

dy/dt = d/dt (t²) - d/dt (2)

Applying the power rule:

dy/dt = 2t - 0

Hence, dy/dt equals 2t. Option b) correctly represents the derivative of y with respect to t.

User Micheal Hill
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