Answer:
The y-intercept for the quadratic function y=x2−3x+2y=x2−3x+2 is (A) (0, 2).
Explanation:
In a quadratic function in the form y=ax2+bx+cy=ax2+bx+c, the y-intercept occurs when xx is equal to 0. Plugging in x=0x=0 into the given quadratic function results in y=2y=2. Therefore, the y-intercept is at the point (0, 2), as the function intersects the y-axis at this coordinate.
It's important to understand that the y-intercept represents the value of the function when xx is zero, which corresponds to the point where the graph crosses the y-axis.
Option A is correct.