185k views
4 votes
If tan(θ)=− 40/9and π <θ<π , what is the exact value of ⁡cos(2θ)?

A) - 1919/1600
B) - 1591/1600
C) 1591/1600
D) 1919/1600



User WeAreOne
by
7.9k points

1 Answer

7 votes

Final answer:

To find the exact value of ⁡cos(2θ), we can use the double-angle identity for cosine: cos(2θ) = cos²(θ) - sin²(θ). Given that tan(θ) = -40/9 and π < θ < π, we can determine the values of sin(θ) and cos(θ) using the Pythagorean identity. Substituting these values into the double-angle identity, we find that the exact value of ⁡cos(2θ) is -1519/1681.

Step-by-step explanation:

To find the exact value of ∧cos(2θ), we can use the double-angle identity for cosine: cos(2θ) = cos²(θ) - sin²(θ).

Given that tan(θ) = -40/9 and π < θ < π, we can determine the values of sin(θ) and cos(θ) using the Pythagorean identity: sin²(θ) + cos²(θ) = 1.

sin(θ) = -40/41 and cos(θ) = 9/41.

Substituting these values into the double-angle identity, we get:

cos(2θ) = (9/41)² - (-40/41)² = 81/1681 - 1600/1681 = -1519/1681.

Therefore, the exact value of ∧cos(2θ) is -1519/1681. Answer choice (A) -1919/1600 is the closest approximation, but not the exact value.

User Decasteljau
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.