Question

What is log cube root of 6 in fraction form.

Answer 1

`\Large \textsf{Read below}`

Step-by-step explanation:

`\Large \text{$ \sf log\:\sqrt[\sf 3]{\sf 6} = log\:6^{(1)/(3)}$}`

`\Large \text{$ \sf log\:\sqrt[\sf 3]{\sf 6} = (1)/(3)\:.\:log\:6$}`

`\Large \boxed{\boxed{\text{$ \sf log\:\sqrt[\sf 3]{\sf 6} = (log\:6)/(3)$}}}`

Answer 2

The log cube root of 6 in fraction form is approximately 0.7782.

Step-by-step explanation:

The log cube root of 6 can be expressed as log3(6). To find this value in fraction form, we can use the property of logarithms that allows us to rewrite the expression as a fraction:

log3(6) = log(6) / log(10)

Step 1: Calculate the logarithm of 6 using a calculator. This gives us a value of approximately 0.7782.

Step 2: Calculate the logarithm of 10 using a calculator. This gives us a value of 1.

Step 3: Divide the logarithm of 6 by the logarithm of 10 to get the fraction form:

log3(6) ≈ 0.7782 / 1 = 0.7782