74.8k views
0 votes
Find the rate of change between 2 and 5 for f(x)= root (2x-3) X 5.

User Jon Wei
by
8.3k points

1 Answer

1 vote

Final answer:

To find the rate of change for the function f(x) = 5√(2x-3) between x = 2 and 5, substitute these values into the function to calculate the average rate of change. The correct formula is (f(5) - f(2)) / (5 - 2).

Step-by-step explanation:

The question asks to find the rate of change of the function f(x) = √(2x-3) × 5 between x = 2 and x = 5. To find this, you would calculate the average rate of change using the function's values at these points. This involves substituting x = 2 and x = 5 into the function to get f(2) and f(5), respectively, and then using the formula:

average rate of change = ∆f / ∆x = (f(5) - f(2)) / (5 - 2)

However, there seems to be a difficulty with the function as provided. The expression √(2x-3) × 5 does not appear to be properly formatted as it combines a square root and multiplication in a manner that is unclear. Assuming the function should be f(x) = 5√(2x-3), we can proceed:

f(2) = 5√(2×2 - 3) = 5√1 = 5

f(5) = 5√(2×5 - 3) = 5√7

Now, calculate the average rate of change:

average rate of change = (5√7 - 5) / (5 - 2) = (5(√7 - 1)) / 3

This gives the average rate of change of the function between x = 2 and x = 5.

User Eugenie
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories