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Find all horizontal tangent lines of graph 3x² 2yt²=16

User Givi
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Final answer:

Without a correct function for y, we cannot find the horizontal tangent lines for the equation provided. Normally, we would differentiate the equation with respect to x and set the derivative of y equal to zero to solve for y.

Step-by-step explanation:

To find all the horizontal tangent lines of the graph given by the equation 3x² + 2yt² = 16, we must first differentiate the equation with respect to x, treating y as a function of x (implicit differentiation).

  1. Differentiate both sides of the equation with respect to x.
  2. Set the derivative of y with respect to x (dy/dx) to zero since the slope of a horizontal line is 0.
  3. Solve for y, the points where the horizontal tangents occur.

However, as the given question seems to contain a typo and is missing a clear function definition for y, we cannot provide a precise solution. If the given function were correctly stated, the mentioned steps would be applicable.

User Parth Raval
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