Final answer:
Roger's bus trip lasts 3 hours and 38 minutes. To find this, the start and end times are converted into a 24-hour format, and the difference in hours and minutes is calculated.
Step-by-step explanation:
To calculate how long Roger's bus trip takes, we need to subtract the time the bus leaves from the time it arrives at Roger's stop. The bus leaves at 9:27 am and arrives at 1:05 pm. There are several steps to find the duration:
- First, we convert the times into a 24-hour format to make subtraction easier. So, 9:27 am remains 9:27, and 1:05 pm becomes 13:05.
- Next, we subtract the start time from the end time.
- This requires handling the hours and minutes separately. If we subtract directly, we have 13:05 - 9:27.
- To avoid negative minutes, we can 'borrow' an hour from the hours, turning the calculation into 12:65 (since 1 hour equals 60 minutes) - 9:27.
- Now, subtract the minutes: 65 - 27 = 38 minutes.
- Then, subtract the hours: 12 - 9 = 3 hours.
- Finally, we combine the hours and minutes to find the total duration: 3 hours and 38 minutes.
Therefore, the duration of Roger's bus trip is 3 hours and 38 minutes.