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Let y = ∛(x⁵). What is dy/dx when x = 8?

a) 15
b) 12
c) 10
d) 8

User JaanusSiim
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1 Answer

6 votes

Final answer:

To find dy/dx, we can use the chain rule for differentiation. The derivative of y = u^(1/3) is (1/3) * u^(-2/3). The derivative of u = x^5 is du/dx = 5x^4.

Step-by-step explanation:

To find dy/dx, we can use the chain rule for differentiation. If we let u = x^5, then we have y = u^(1/3).

Using the chain rule, dy/dx = (dy/du) * (du/dx).

The derivative of y = u^(1/3) is dy/du = (1/3) * u^(-2/3).

The derivative of u = x^5 is du/dx = 5x^4.

Substituting these values into the chain rule equation, we have dy/dx = (1/3)*(u^(-2/3))*(5x^4).

When x = 8, we can substitute this value into the equation to find the derivative.

Therefore, dy/dx = (1/3)*(8^(5/3))^(-2/3)*(5(8^4)).

User Nikhil Zurunge
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