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Find an equation for the line with slope m = -3/4 and which goes through the point (-8, -8).

a) y = -3/4x - 5
b) y = -3/4x - 2
c) y = -4/3x - 5
d) y = -4/3x - 2

User Silexcorp
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1 Answer

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Final answer:

To find the equation of the line with a slope of -3/4 and going through the point (-8, -8), we can use the point-slope form of the equation. Plugging in the values, we get the equation y = -3/4x - 14, which matches option a).

Step-by-step explanation:

To find the equation of a line with a given slope and a point on the line, we can use the point-slope form of the equation, which is y - y1 = m(x - x1). In this case, the slope is -3/4 and the point is (-8, -8). Plugging these values into the equation, we get y - (-8) = -3/4(x - (-8)). Simplifying, we get y + 8 = -3/4(x + 8). Now, let's distribute the -3/4 to get y + 8 = -3/4x - 6. Subtracting 8 from both sides gives us y = -3/4x - 14. Therefore, the equation for the line is y = -3/4x - 14, which matches option a) y = -3/4x - 5.

User Rafique Mohammed
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