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Write the standard form for the ellipse given by 9x² + 25y² - 90x - 200y - 400 = 0.

a) (x-5)²/25 + (y-4)²/9 = 1
b) (x+5)²/9 + (y-4)²/25 = 1
c) (x-5)²/9 + (y+4)²/25 = 1
d) (x+5)²/25 + (y+4)²/9 = 1

User Htellez
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1 Answer

4 votes

Final answer:

To find the standard form of the given ellipse equation, we complete the square for x and y terms and simplify to end up with (x-5)²/25 + (y-4)²/9 = 1. Therefore, the correct answer is Option a.

Step-by-step explanation:

The student is asking to rewrite the equation of an ellipse in standard form. The standard form of an ellipse equation is (x-h)²/a² + (y-k)²/b² = 1, where (h, k) is the center of the ellipse, and a and b are the lengths of the semi-major and semi-minor axes, respectively.

To convert the given equation 9x² + 25y² - 90x - 200y - 400 = 0 into standard form, we need to complete the square for both x and y terms. First, we group the x terms and the y terms:

9(x² - 10x) + 25(y² - 8y) = 400

Next, we add the squares of half the coefficients of x and y to complete the square:

9[(x - 5)² - 25] + 25[(y - 4)² - 16] = 400

We then simplify the equation by distributing and moving constants to the other side:

9(x - 5)² + 25(y - 4)² - 225 - 400 = 400

9(x - 5)² + 25(y - 4)² = 625

Finally, we divide by 625 to get the standard form:

(x - 5)²/25 + (y - 4)²/9 = 1

Therefore, the correct answer is Option a: (x-5)²/25 + (y-4)²/9 = 1.

User GaspardP
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