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What is the antiderivative F of the function
f(x)=9e^x, given that F(0)=0?

User Hugh Allen
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1 Answer

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Final answer:

The antiderivative of the function f(x) = 9e^x is F(x) = 9e^x, and it satisfies F(0) = 0.

Step-by-step explanation:

The antiderivative F of the function f(x) = 9e^x is found by applying the power rule of integration. The power rule states that the antiderivative of a function of the form f(x) = ax^n is given by F(x) = (a/n)x^(n+1). In this case, we have f(x) = 9e^x, so applying the power rule, we get F(x) = (9/1)e^x = 9e^x. Since we are given that F(0) = 0, we can substitute x = 0 into the antiderivative to find the constant of integration. So, 0 = 9e^0 = 9, which implies that the constant of integration is 0. Therefore, the antiderivative F(x) = 9e^x satisfies F(0) = 0.

User Veereev
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