Question

G(x)=2x² - 16x + 31 achieves its minimum at:

a) x = -4
b) x = 4
c) x = -2
d) x = 2

Answer 1

The function g(x) = 2x² - 16x + 31 achieves its minimum at x = 4.

Step-by-step explanation:

To find the minimum of the function g(x) = 2x² - 16x + 31, we can use the formula for the x-coordinate of the vertex of a quadratic function, which is given by x = -b/2a. In this case, a = 2 and b = -16, so the x-coordinate of the vertex is x = -(-16)/(2(2)) = 4. Therefore, the function achieves its minimum at x = 4.