79.1k views
0 votes
Which is the center and radius of the circle given by the equation, x² + y² - 6x - 10y + 11 = 0?

a) Center: (³, ⁵), Radius: √²¹
b) Center: (-³, -⁵), Radius: √²¹
c) Center: (-³, -⁵), Radius: √³¹
d) Center: (³, ⁵), Radius: √³¹

User Androphone
by
7.9k points

1 Answer

3 votes

Final answer:

The center of the circle is (3, 5) and the radius is √23.

Step-by-step explanation:

The equation of the given circle is x² + y² - 6x - 10y + 11 = 0.

To find the center and radius, we rearrange the equation in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

Completing the square for the x terms, we have (x - 3)² + (y - 5)² = 9 + 25 - 11 = 23.

Therefore, the center of the circle is (3, 5) and the radius is √23.

User Thangcao
by
7.7k points