Final answer:
The resistance of five 240Ω resistors connected in series is 1200Ω.
Step-by-step explanation:
The resistance of five 240Ω resistors connected in series can be calculated by simply adding up the resistances. In a series circuit, the total resistance is the sum of the individual resistances. Thus, the total resistance of the five 240Ω resistors connected in series would be:
240Ω + 240Ω + 240Ω + 240Ω + 240Ω = 1200Ω
Therefore, the correct answer is c) 1200Ω.