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In the circuit of figure 3, the energy absorbed in the 2-2 resistor over the course of one minute and 20 seconds is 10 J. Find the resistance R. "A" is the right answer. However, I can't figure out how to do it ​

In the circuit of figure 3, the energy absorbed in the 2-2 resistor over the course-example-1

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To find the resistance, we can use the formula for power in a circuit, which is given by P = V^2 / R. Given the energy absorbed and the time, we can calculate the power. Once we have the power, we can rearrange the formula to solve for the resistance R.

Step-by-step explanation:

To find the resistance, we can use the formula for power in a circuit, which is given by P = V^2 / R, where P is the power, V is the voltage, and R is the resistance.

Given that the energy absorbed in the 2-2 resistor over one minute and 20 seconds is 10 J, we can calculate the power using the formula P = E / t, where E is the energy and t is the time.

Since the power is given as 10 J, and the time is 1 minute and 20 seconds (which is equivalent to 80 seconds), we can plug these values into the formula to find the power.

Once we have the power, we can rearrange the formula to solve for the resistance R.

Using the equation P = V^2 / R, we can substitute the values for P, V (which is given in the problem), and solve for R.

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