Final answer:
The coefficient of Al(OH)3 in the balanced equation of Al2(SO4)3 and NaOH reacting is 2, indicating two moles of aluminum hydroxide are produced.
Step-by-step explanation:
To determine the correct coefficient of Al(OH)3 in the balanced equation Al2(SO4)3 + NaOH + Al(OH)3 + Na2SO4, we first need to balance the equation correctly. However, the given equation is incomplete and doesn't show the products and reactants properly aligned to demonstrate the full reaction. It is important to write a complete balanced chemical equation before determining the coefficients. Assuming we are balancing the reaction of aluminum sulfate with sodium hydroxide, which produces aluminum hydroxide and sodium sulfate, an example of a correctly balanced equation might look like this: Al2(SO4)3 + 6NaOH -> 2Al(OH)3 + 3Na2SO4. In this balanced equation, the coefficient of Al(OH)3 is 2, indicating that two moles of aluminum hydroxide are produced.