Final answer:
The net ionic equation for the reaction between aluminum sulfate and sodium phosphate is 2Al^{3+}(aq) + 2PO4^{3-}(aq) → 2AlPO4(s), which shows the formation of solid aluminum phosphate from aqueous aluminum and phosphate ions.
Step-by-step explanation:
The prompt asks for the net ionic equation for the reaction between aluminum sulfate and sodium phosphate. To address this, we first need to write the overall chemical equation, then express it as a complete ionic equation before we can identify the net ionic equation. However, the prompt provides examples involving other reactions, which could cause confusion, but the key components of the net ionic equation we are looking for involve the formation of a precipitate when aluminum ions react with phosphate ions.
In the case of aluminum sulfate reacting with sodium phosphate, the overall balanced chemical equation would look like:
Al2(SO4)3(aq) + 2Na3PO4(aq) → 2AlPO4(s) + 3Na2SO4(aq)
This shows aluminum phosphate precipitating out while sodium sulfate stays in solution. Breaking it down into the complete ionic equation, we have:
2Al^{3+}(aq) + 6SO4^{2-}(aq) + 6Na^{+}(aq) + 2PO4^{3-}(aq) → 2AlPO4(s) + 6Na^{+}(aq) + 3SO4^{2-}(aq)
By canceling out the spectator ions (those ions that do not change during the reaction), we acquire the net ionic equation:
2Al^{3+}(aq) + 2PO4^{3-}(aq) → 2AlPO4(s)