Final answer:
The equation sin z = 2 cannot have a solution in real numbers as the sine function's range is between -1 and 1. Hence, there is no real value of z that satisfies this equation.
Step-by-step explanation:
The student has asked to solve the equation sin z = 2. In standard mathematical practice, the sine of an angle cannot be greater than 1 or less than -1 since it corresponds to the y-coordinate on the unit circle, where the maximum and minimum values on the y-axis are 1 and -1, respectively. Therefore, no real number solution exists for the equation sin z = 2.
However, if we were to consider complex numbers, which is a college-level topic, the solution would involve finding a complex number z where the imaginary part allows for the sine to take on a value greater than 1.
This involves using the definition of sine in the complex plane which is beyond high school mathematics. But in high school, we typically state that such an equation has no solution in the context of real numbers.