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How to convert a linear equation from slope-intercept form to standard form?

User ASk
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Final answer:

To convert an equation from slope-intercept form (y = mx + b) to standard form (Ax + By = C), subtract mx from both sides, clear any fractions, and adjust the equation so that A is a positive integer.

Step-by-step explanation:

To convert a linear equation from slope-intercept form to standard form, you can follow these general steps:

  1. Start with the slope-intercept form of the equation, which is typically written as y = mx + b where m is the slope and b is the y-intercept.
  2. Rearrange this equation to get the x and y variables on one side of the equation. This often involves subtracting mx from both sides to give y - mx = b.
  3. Now you need to get rid of any fractions, so if your equation includes fractions, multiply all terms by the denominator to clear them.
  4. Finally, standard form is typically written as Ax + By = C, where A, B, and C are integers, and A is non-negative. If A is negative, you can multiply the entire equation by -1 to make it positive.

As an example, let's convert the slope-intercept equation y = 3x + 9 to standard form. We can subtract 3x from both sides to get -3x + y = 9. Then, if we want A to be positive, we can multiply through by -1 to get 3x - y = -9, which is now in standard form.

In another example, if your equation is y = 55x + 75, subtracting 55x from both sides yields -55x + y = 75. Multiplying through by -1, the equation in standard form becomes 55x - y = -75.

User Elkvis
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