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A 2.50 kg box is pulled by a constant force of 16 N that is exerted at an angle 36.9° above the horizontal. The box has moved a distance of 3.00 m along a horizontal surface whose coefficient of kinetic friction is 0.21.

(a) What is the total work done on the box?

User Shinnc
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1 Answer

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The total work done on the box is determined as 53.82 J.

How to calculate the total work done on the box?

The total work done on the box is calculated by applying the following formula as shown below.

W(total) = Work done applied force + work done by friction

The work done by the applied force is calculated as;

W (applied) = Fd cosθ

where;

  • F is the applied force
  • d is the displacement
  • θ is the angle of inclination

W = 16 N x 3 m x cos (36.9)

W = 38.38 J

The work done by the force of friction is calculated as;

W = μmgd

where;

  • μ is the coefficient of friction
  • m is the mass
  • g is acceleration due to gravity
  • μ is the coefficient of friction

W = 0.21 x 2.5 kg x 9.8 m/s² x 3 m

W = 15.44 J

The total work done;

W (total) = 38.38 J + 15.44 J

W (total) = 53.82 J

User Andy Williams
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