Final answer:
The resistance of a wire of the same material and length but double the diameter will be one-fourth of the original resistance, which is R/4.
Step-by-step explanation:
The subject of this question is in the field of Physics, relating to electrical resistance and the properties of conductive materials. When considering the resistance of a wire, we use the formula R=ρL/A, where R is the resistance, ρ (rho) is the resistivity of the material, L is the length, and A is the cross-sectional area. For a wire with double the diameter, the cross-sectional area, which is π(d/2)^2, will increase by a factor of 4, since the radius (half of the diameter) is doubled. Given that the length and the material (and thus the resistivity) remain constant, and resistance is inversely proportional to the area, the new resistance will be one-fourth of the original resistance, or R/4.