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What is the probability of selling 25 cheesecakes if the options are 0.25, 0.50, 0.75, and 1.00?

a) 0.25
b) 0.50
c) 0.75
d) 1.00

1 Answer

6 votes

Final answer:

The probability of the specific event regarding cheesecake sales is not determinable with the provided information. Understanding different probability rules and scenarios, such as mutually exclusive events and conditional probabilities, is essential in solving the given examples.

Step-by-step explanation:

Based on the various examples provided in the question, we are dealing with the concept of probability. Without additional context for the specific question regarding the sale of 25 cheesecakes, we cannot provide an accurate answer to that scenario. Instead, let's address some of the examples provided which involve calculating probabilities in various contexts. For instance, if we look at the example where H and D are mutually exclusive events, with P(H) = 0.25 and P(D) = 0.15, the probability of both events happening together, denoted as P(HD), is 0 since mutually exclusive events cannot occur simultaneously.

Another example provided is a conditional probability problem: P(x > 21| x > 18). To solve this, you set the new lower limit to 18 since you're given that x is already greater than 18, and you would calculate the probability from there. These examples all require an understanding of basic probability rules including the addition rule, complement rule, and principles of conditional probability and expected value.

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