Final answer:
The density function of √u when u is uniformly distributed on [0, 1] is 2√u.
Step-by-step explanation:
To find the density function of √u when u is uniformly distributed on the interval [0, 1], we can use the method of transformation.
Let's consider the cumulative distribution function (CDF) of √u, denoted as F(√u). The CDF of u is F(u) = u for u in [0, 1]. Therefore, the CDF of √u can be calculated as:
F(√u) = P(√u ≤ x) = P(u ≤ x^2) = F(x^2) = x^2,
where x is a value in the interval [0, 1]. Finally, the density function of √u is the derivative of F(√u) with respect to x:
f(√u) = d/dx(x^2) = 2x.
Therefore, the density function of √u is 2√u.