Final answer:
E1 is confirmed to be exactly twice the magnitude of E2, as indicated by the arrow representing E1 being twice as long as that for E2, so the correct answer to the question is that E1 > E2.
Step-by-step explanation:
The given information indicates that the electric field strength E₁ is exactly twice the magnitude of E2. It is stated that the arrow representing E₁ is twice as long as that of E2, indicating that E₁ has a greater magnitude. Therefore, the correct comparison of the electric field strengths of the two segments implies that E1 > E2.
When considering the representation of electric fields from charges, fields in the same direction add to each other, making the resulting field stronger, while fields in opposite directions subtract from each other, making the resulting field weaker. Applying this principle to two positive charges, the electric field further away from the charges (where the fields from the individual charges oppose) would be weaker than the field close to the charges (where the fields add up). Hence, in regions where electric fields are additive, we can conclude a stronger electric field strength, while subtractive regions would result in a weaker electric field strength.
Lastly, discussing the relationship between E-field and B-field strengths, it is noted that a stronger E-field will generally lead to a greater B-field in the context of electromagnetic waves.