Final answer:
The dimensions of the rectangular page that contains 64 square inches of print with the length being twice the width are 8 inches by 16 inches.
Step-by-step explanation:
The question is asking for the dimensions of a rectangular page that must contain 64 square inches of print, given that the length is twice the width. To solve this, we'll denote the width as x inches. Consequently, the length would be 2x inches. Because the area of a rectangle is found by multiplying the length by the width, we can set up the equation x × 2x = 64. Solving for x, we find that x² = 32, and thus x = 8 inches. This makes the length 16 inches, as it is double the width. Therefore, the correct dimensions of the page are 8 inches by 16 inches, which corresponds to option A: 4 inches by 16 inches, given that the length should be twice the width.