Question

What volume of a 0.100M HCl stock solution should be used to prepare 250.00ml of 0.0250M HCl?

A. 2.5 mL
B. 10.0 mL
C. 25.0 mL
D. 100.0 mL

Answer 1

Using the dilution equation C1V1 = C2V2, it was calculated that 62.50 ml of 0.100M HCl stock solution is needed to prepare 250.00 ml of 0.0250M HCl. However, none of the provided options match this result.

Step-by-step explanation:

To determine which volume of a 0.100M HCl stock solution is needed to prepare 250.00 mL of 0.0250M HCl, we can use the dilution equation C1V1 = C2V2, where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the diluted solution, respectively.

Given values:

• C1 = 0.100M (stock solution)
• C2 = 0.0250M (desired solution)
• V2 = 250.00ml (desired solution volume)

Using the equation, we can solve for V1:

V1 = (C2 × V2) / C1
V1 = (0.0250M × 250.00ml) / 0.100M
V1 = 62.50ml / 0.100M
V1 = 62.50 ml

Looking at the multiple-choice options provided, none exactly match 62.5 ml, indicating there might be a typo in the question options or in the calculations.