Final answer:
The student's question involves creating a solid of revolution by rotating the area under the curve y=√x from x=0 to x=36 around the line x=36. The resulting shape is a torus-like solid, which can be calculated using the washer or cylindrical shell method.
Step-by-step explanation:
The student is asking to find the solid of revolution obtained by revolving the region bounded by the graph of y=√x, the line y=0, and x=36 around the line x=36. To visualize the solid, we consider the shape formed when the area under the square root function from x=0 to x=36 is revolved around the vertical line x=36.
The solid of revolution will resemble a donut shape, technically known as a torus, where the hole of the donut aligns with the line x=36, and the outer radius extends from x=36 to the curve y=√x.
To calculate the volume of this solid, we would typically use the washer method where an integral would represent the volume of thin washers stacked along the axis of rotation.
However, since the bounds y=0 and x=36 form a rectangular region, if revolved, they would form a cylindrical shell. This particular situation might actually be better approached by the cylindrical shell method than the washer method because the axis of rotation is vertical.