Final answer:
The question lacks context and cohesive information to accurately solve for the length 's'. However, one instance provided suggests calculating the sample standard deviation, with an example resulting in 's = .716' after rounding to three decimal places. For precise solutions, carry calculations to at least three decimal places before rounding off.
Step-by-step explanation:
The question is asking to solve for the variable 's,' which likely represents a length or a standard deviation in a mathematical context. The difficulty in providing a step-by-step solution arises from the fact that the information provided is very fragmented and does not cohesively tie into a singular problem. The various snippets suggest different contexts: scaling from a diagram, the standard deviation in statistics, and calculations involving significant figures.
Without a specific problem or context, providing an accurate answer isn't feasible. However, a general approach to find the length 's' could involve using geometry or algebra to solve for 's' in an equation, or calculating statistical measures such as the sample standard deviation, which involves finding the square root of the sample variance.
The process would generally look like this: assessing the given information, formulating the appropriate equation or statistical formula, and solving for 's' with correct significant figures and rounding conventions. In practical terms, for standard deviation, the formula S = √.5125 leads to S = .715891, which when rounded to three decimal places, yields s = .716. This emphasizes the importance of carrying calculations to at least three decimal places before rounding off for the final answer to minimize errors.