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What is the pH of a 10.8 M NaOH?

a. Need the Kb to solve this problem and you did not provide one.
b. Need the Ka to solve this problem and you did not provide one.
c. 1.03
d. 15.03
e. 12.97

1 Answer

5 votes

Final answer:

The pH of a 10.8 M NaOH is 15.03. Therefore, the correct answer is (d) 15.03

Step-by-step explanation:

The pH of a 10.8 M NaOH can be calculated by first calculating the concentration of H3O+ ions using the formula [H3O+] = 10^-14 / [OH-].

In this case, since the concentration of NaOH is the same as the concentration of OH-, we can use the given concentration of NaOH to calculate [H3O+].

Using the formula [H3O+] = 10^-14 / [OH-], we get [H3O+]

= 10^-14 / 10.8

= 9.26 x 10^-16 M

Finally, to find the pH, we can use the formula pH = -log[H3O+]. pH

= -log(9.26 x 10^-16)

= 15.03

User Jorge Rivera
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