Final answer:
The pH of a 10.8 M NaOH is 15.03. Therefore, the correct answer is (d) 15.03
Step-by-step explanation:
The pH of a 10.8 M NaOH can be calculated by first calculating the concentration of H3O+ ions using the formula [H3O+] = 10^-14 / [OH-].
In this case, since the concentration of NaOH is the same as the concentration of OH-, we can use the given concentration of NaOH to calculate [H3O+].
Using the formula [H3O+] = 10^-14 / [OH-], we get [H3O+]
= 10^-14 / 10.8
= 9.26 x 10^-16 M
Finally, to find the pH, we can use the formula pH = -log[H3O+]. pH
= -log(9.26 x 10^-16)
= 15.03