Final answer:
In this reaction, mercury(II) nitrate (Hg(NO3)2) reacts with sodium sulphide (Na2S) to form a product. The balanced chemical equation for this reaction is: Hg(NO3)2 + Na2S → HgS + 2NaNO3. The mass of the product formed can be calculated using the given mass of mercury(II) nitrate and the molar masses of the reactants and products.
Step-by-step explanation:
In this reaction, mercury(II) nitrate (Hg(NO3)2) reacts with sodium sulphide (Na2S) to form a product. The balanced chemical equation for this reaction is:
Hg(NO3)2 + Na2S → HgS + 2NaNO3
From the equation, we can see that 1 mole of Hg(NO3)2 reacts with 1 mole of Na2S to form 1 mole of HgS. To calculate the mass of HgS formed, we need to first calculate the number of moles of Hg(NO3)2 present.
The molar mass of Hg(NO3)2 is 2 x (atomic mass of Hg) + 6 x (molar mass of NO3) = 2 x 200.59 g/mol + 6 x (14.01 g/mol + 16.00 g/mol) = 2 x 200.59 g/mol + 6 x 30.01 g/mol = 401.18 g/mol + 180.06 g/mol = 581.24 g/mol.
Given that the mass of Hg(NO3)2 is 2g, we can use the following equation to calculate the number of moles of Hg(NO3)2:
Number of moles = Mass / Molar mass = 2g / 581.24 g/mol = 0.0034 mol.
Since 1 mole of Hg(NO3)2 reacts with 1 mole of HgS, we can conclude that 0.0034 moles of Hg(NO3)2 will react to form 0.0034 moles of HgS.
The molar mass of HgS is the atomic mass of Hg plus the atomic mass of S, which is 200.59 g/mol + 32.07 g/mol = 232.66 g/mol.
Using the equation Number of moles = Mass / Molar mass, we can calculate the mass of HgS:
Mass = Number of moles x Molar mass = 0.0034 mol x 232.66 g/mol = 0.791 g